Like

Report

Suppose that 2 J of work is needed to stretch a spring from its natural length of 30 cm to a length of 42 cm.

(a) How much work is needed to stretch the spring from 35 cm to 40 cm?

(b) How far beyond its natural length will a force of 30 N keep the spring stretched?

(a) $$

W \approx 1.04 J

$$

(b) $$

10.8 \mathrm{cm}

$$

Applications of Integration

You must be signed in to discuss.

Bruce Z.

September 18, 2021

how do u calculate K value

R T.

September 26, 2021

where are these values derived from???

Missouri State University

University of Michigan - Ann Arbor

Idaho State University

Okay, So the first things who calculates Spring Constant K here recalled the hooks law. That app equals to chaos. Okay, Okay. And this is the X equals two 42 minus 30. He was 12 or zero on one's half meter. That centimeter fell Seven articles to 011 will be there. And we know that the work this, what has done is to to Jules, that equals to zero to Europe on one to text e x every self okay. By this equation, gonna have K equals two approximately equals to 280 278. It's over, Kay. And four, the part B Barbie is through Catholic. It's the work that zone by the same spring, but from different position from, uh, 0 to 011 meter. And, uh, that equals two 1.416 seven draw. Approximately

University of Illinois at Urbana-Champaign

Applications of Integration